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Problems #5,6 are graded.

Problem 5: Let {ak}k=0={13k}k=0 and {bk}k=0={17k}k=0. Then compute using geometric series: {ak},{bk}=k=013k17k=k=0(121)k=11121=2120. Now let {ck}k=0={1k!}. Using the fact that ex=k=0xkk! we see that e1=e=k=01k!. Now we may compute {1k!},{1k!}=k=01k!1k!=k=01k!=e. Problem 6: Let x=5+4i and y=21+16i. Compute x,y=(5+4i)¯(911i)=(5+4i)(9+11i)=45+55i+36i+44i2=45+91i44=1+91i. Let z1=21+16i and notice z2=115i2+i=115i2+i2i2i=2211i10i+5i24i2=1721i5=175215i. Now compute z1,z2=(21+16i)¯(175215i)=(21+16i)(175+215i)=3575+4415i+2725i+3365i2=215+7135i.