Response | Number of times, $f$ |

Very prepared | 259 |

Somewhat prepared | 952 |

Not too prepared | 552 |

Not at all prepared | 336 |

Not sure | 63 |

Ages of voters | Frequency, $f$ (in millions) |

18 to 20 | 4.2 |

21 to 24 | 7.9 |

25 to 34 | 20.5 |

35 to 44 | 22.9 |

45 to 64 | 53.5 |

65 and over | 28.3 |

Ages | Frequency, $f$ |

0-14 | 38 |

15-29 | 20 |

30-44 | 31 |

45-59 | 53 |

60-74 | 36 |

75 and over | 15 |

$$38+20+31+53+36+15=193.$$ Now the requested probability is $$\dfrac{38+31+53+36+15}{193} = \dfrac{173}{193}=0.8963.$$

From this we see there are a total of 24 possible outcomes (count the lines at the bottom). There is exactly one way to roll a 5 and land on blue, so the probability being requested is $$\dfrac{1}{24}=0.04166.$$